Well, nice pic indeed. But why is the circled
part so? I mean where does (1+(gamma²/2)+...)
come from? (I have not studied relativity that much, I
am just curious. But then again I think it is
more of a mathematical approssimation which
anyway I don't get.)
That's the Lorentz Factor (en.wikipedia.org/wiki/Lorentz_factor). What this development does is bringing a
"classic" equation for the kinetic
energy from a relativistic equation (top
left). The only assumption is that velocity
is way smaller than the speed of light (v
<< c, that is gamma << 1). Hope
it helps.
Ok, that's great. Thanks. I did read the
link, without actually grasping a lot of it
though (silly me). The part of the picture that troubles me is
when you go from [(1-γ²)^(-1/2)] to
[(1+γ²/2)+...]. I do have some reminiscences from physics
class of the first substitutions in the first
two rows, but I don't get that particular
approximation. Is there any chance you could explain it
simply to a physics noob like me?
Not a problem. That's called a Taylor series
approximation (en.wikipedia.org/wiki/Taylor_series). Basically, when you do such an
approximation, the first few terms in the
series account for most of the value of the
function at a particular point. In our case,
we're assuming that v (velocity) is way
smaller than the speed of light (this is
called "classic conditions"), and
so v/c is very close to zero. Therefore, we
can do a Taylor series approximation "at
gamma = 0".
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thayermm added this photo to her favorites. (16 months ago)
WaTTacK (12 months ago | reply)
Well, nice pic indeed. But why is the circled part so? I mean where does (1+(gamma²/2)+...) come from?
(I have not studied relativity that much, I am just curious. But then again I think it is more of a mathematical approssimation which anyway I don't get.)
zugaldia (12 months ago | reply)
That's the Lorentz Factor (en.wikipedia.org/wiki/Lorentz_factor). What this development does is bringing a "classic" equation for the kinetic energy from a relativistic equation (top left). The only assumption is that velocity is way smaller than the speed of light (v << c, that is gamma << 1). Hope it helps.
WaTTacK (12 months ago | reply)
Ok, that's great. Thanks. I did read the link, without actually grasping a lot of it though (silly me).
The part of the picture that troubles me is when you go from [(1-γ²)^(-1/2)] to [(1+γ²/2)+...].
I do have some reminiscences from physics class of the first substitutions in the first two rows, but I don't get that particular approximation.
Is there any chance you could explain it simply to a physics noob like me?
zugaldia (12 months ago | reply)
Not a problem. That's called a Taylor series approximation (en.wikipedia.org/wiki/Taylor_series). Basically, when you do such an approximation, the first few terms in the series account for most of the value of the function at a particular point. In our case, we're assuming that v (velocity) is way smaller than the speed of light (this is called "classic conditions"), and so v/c is very close to zero. Therefore, we can do a Taylor series approximation "at gamma = 0".
You can see the complete result from Wolfram Alpha (www.wolframalpha.com/input/?i=taylor%5B%281-x %5E2%29%5E%2...).
WaTTacK (11 months ago | reply)
Oh, that was it. That's why I couldn't understand it, I never studied the Taylor series.
Thanks a lot mate!
zugaldia (11 months ago | reply)
My pleasure.