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The ideas on this page are completely free, I own no patent for them. Feel free to take them for your self. If you are evaluating them please be specific with flaws in the design, not just a law of physics, and teach me where I went wrong (if I went wrong). I am looking for calculations for the output of the motors, note that all the motors are powered by a compressed spring, if not mentioned.

This design is very similar to first perp motion design, only I directed the input in the same direction as the unit for no opposing forces (if there were any).
Fig 1 I am using the same lever, the orange dot is the input.
Fig 2 The crank is changed to this shape, and is all one piece. The red dot is the center of the rotation.
Fig 3 To get all forces flowing in one direction I have crossed the yellow link over the green crank. Input force (down) at the orange dot, it pulls the yellow link, and pushes the bottom of the green crank to the right below the center of rotation.
Fig 4 this is the finished product I have only added the spring (gray) and mount lime green. The mount will be fused to the crank so it will spin with the unit. The spring must be compressed for this to work.
This will spin due to an imbalance in leverage between the input and output and continue to spin because there is no loss of speed. The apparatus rotates counter clockwise.

my idea is to gain leverage without losing speed.
fig 1 is my lever. 10 -1 ratio moving in the direction of the arrows.
Fig 2 is my crank. the red dot is the center of the rotation and yellow and purple dots connect to there match of the lever of fig 1 by "push bar" links. the elbows connected to these dots are the output of the system.
fig 3 is the finished product, the green dot is the input.
Fig 4 shows that the unit rotates as one.
Note there is friction in this apparatus but you have an output greater than the input and the friction.
Also this system needs an input force my idea was to compress a spring between the input and output and have it spin with the apparatus.

briefly if you believe that the 10-1 lever is producing more than 3x the input in the direction of the arrow at the red pivot point, my idea works.
Fig 1 my idea is to use two separate levers to gain leverage without losing speed.
Fig 2 is how I plan on doing this. I have bent the 10-1 lever into a 90, this will change the direction of travel of output to better suit the crank.
Fig 3 is the crank in blue are open joints to allow the 90 lever to apply force to the crank. In the design if one blue joint is missing the 90 lever will hang limp. both black angles are fused together.
Fig 4 is the finished product in yellow is a "push bar", this gives the proper angle of force on the crank. the bottom angle of the crank is not parallel to the length of the 90 lever this will keep both outputs of the 90 from opposing each other. the whole apparatus revolves around red cross.
Sizes: 90 lever 10" to 1:", top angle of crank 7" bottom angle 11", yellow push bar 7"
The main idea is to gain leverage without losing speed. This is two separate levers moving as one, with both levers (90 and crank) gaining leverage.

Briefly if you believe that the lever of Fig 2 is creating more than 22lbs of leverage in the direction of both arrows than you believe my idea works.
My goal is to gain leverage without losing speed.
Fig 1 show an ordinary 10-1 lever. The basic idea of my invention is to use the fucrum and the output of this lever to power a crank. To do this I must get the direction of travel of the fulcrum and the output in the same direction. I call it the hammer lever.
Fig 2 what I did was bent our ordinary lever into a 90 with the fulcrum at the elbow. This will change the direction of travel, marked by the arrows, to better suit our needs. Sized 10" to 1".
Fig 3 show the crank with the red x showing the center of rotation. The 45 is 10" long and the bottom pointing down would be 1". In blue will be the pivot point for our links.
Fig 4 is the final product basicly linking the hammer lever to the crank with links in yellow. In blue are pivot points. How it works the 90 on the hammer lever pulls the 45 on top of the crank to the left and the output pushes the bottom of the crank to the right, just like Fig 2. The whole thing moves as a unit around the red x marked by the orange arrow. Also note the yellow links do not move they just apply the force from the hammer lever to the crank.
Output: the length from the green dot to the red x is about 24", 10" in the lever and 14" from the lever to the x (for the proper angle from the fulcrum to the 45 on the top of the crank). 10 lbs at 24" is 240 inch lbs. To scrutinize my idea, the hammer lever would have to transfer less than 22 lbs to the 10" 45 and 1" bottom of crank, any more than that it will be perpetual motion. I believe it will transfer at least 50 lbs. giving you 550+ inch pounds of torque.

This design needs an input, the spring, but the core is there, I left the spring out to keep it short. Briefly I would compress a spring between the input and the output, and it would spin due to an imbalance in leverage.